tests/ui/specialization/specialization-default-types.rs

//@ revisions: current next
//@ ignore-compare-mode-next-solver (explicit revisions)
//@[next] compile-flags: -Znext-solver

// It should not be possible to use the concrete value of a defaulted
// associated type in the impl defining it -- otherwise, what happens
// if it's overridden?

#![feature(specialization)]

trait Example {
    type Output;
    fn generate(self) -> Self::Output;
}

impl<T> Example for T {
    default type Output = Box<T>;
    default fn generate(self) -> Self::Output {
        Box::new(self) //~ ERROR mismatched types
    }
}

impl Example for bool {
    type Output = bool;
    fn generate(self) -> bool { self }
}

fn trouble<T>(t: T) -> Box<T> {
    Example::generate(t) //~ ERROR mismatched types
}

fn weaponize() -> bool {
    let b: Box<bool> = trouble(true);
    *b
}

fn main() {
    weaponize();
}