| /* | |
| * ==================================================== | |
| * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved. | |
| * | |
| * Developed at SunPro, a Sun Microsystems, Inc. business. | |
| * Permission to use, copy, modify, and distribute this | |
| * software is freely granted, provided that this notice | |
| * is preserved. | |
| * ==================================================== | |
| */ | |
| /* Modifications for 128-bit long double are | |
| Copyright (C) 2001 Stephen L. Moshier <moshier@na-net.ornl.gov> | |
| and are incorporated herein by permission of the author. The author | |
| reserves the right to distribute this material elsewhere under different | |
| copying permissions. These modifications are distributed here under | |
| the following terms: | |
| This library is free software; you can redistribute it and/or | |
| modify it under the terms of the GNU Lesser General Public | |
| License as published by the Free Software Foundation; either | |
| version 2.1 of the License, or (at your option) any later version. | |
| This library is distributed in the hope that it will be useful, | |
| but WITHOUT ANY WARRANTY; without even the implied warranty of | |
| MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU | |
| Lesser General Public License for more details. | |
| You should have received a copy of the GNU Lesser General Public | |
| License along with this library; if not, see | |
| <http://www.gnu.org/licenses/>. */ | |
| /* | |
| * __ieee754_jn(n, x), __ieee754_yn(n, x) | |
| * floating point Bessel's function of the 1st and 2nd kind | |
| * of order n | |
| * | |
| * Special cases: | |
| * y0(0)=y1(0)=yn(n,0) = -inf with division by zero signal; | |
| * y0(-ve)=y1(-ve)=yn(n,-ve) are NaN with invalid signal. | |
| * Note 2. About jn(n,x), yn(n,x) | |
| * For n=0, j0(x) is called, | |
| * for n=1, j1(x) is called, | |
| * for n<x, forward recursion us used starting | |
| * from values of j0(x) and j1(x). | |
| * for n>x, a continued fraction approximation to | |
| * j(n,x)/j(n-1,x) is evaluated and then backward | |
| * recursion is used starting from a supposed value | |
| * for j(n,x). The resulting value of j(0,x) is | |
| * compared with the actual value to correct the | |
| * supposed value of j(n,x). | |
| * | |
| * yn(n,x) is similar in all respects, except | |
| * that forward recursion is used for all | |
| * values of n>1. | |
| * | |
| */ | |
| #include "quadmath-imp.h" | |
| static const __float128 | |
| invsqrtpi = 5.6418958354775628694807945156077258584405E-1Q, | |
| two = 2, | |
| one = 1, | |
| zero = 0; | |
| __float128 | |
| jnq (int n, __float128 x) | |
| { | |
| uint32_t se; | |
| int32_t i, ix, sgn; | |
| __float128 a, b, temp, di, ret; | |
| __float128 z, w; | |
| ieee854_float128 u; | |
| /* J(-n,x) = (-1)^n * J(n, x), J(n, -x) = (-1)^n * J(n, x) | |
| * Thus, J(-n,x) = J(n,-x) | |
| */ | |
| u.value = x; | |
| se = u.words32.w0; | |
| ix = se & 0x7fffffff; | |
| /* if J(n,NaN) is NaN */ | |
| if (ix >= 0x7fff0000) | |
| { | |
| if ((u.words32.w0 & 0xffff) | u.words32.w1 | u.words32.w2 | u.words32.w3) | |
| return x + x; | |
| } | |
| if (n < 0) | |
| { | |
| n = -n; | |
| x = -x; | |
| se ^= 0x80000000; | |
| } | |
| if (n == 0) | |
| return (j0q (x)); | |
| if (n == 1) | |
| return (j1q (x)); | |
| sgn = (n & 1) & (se >> 31); /* even n -- 0, odd n -- sign(x) */ | |
| x = fabsq (x); | |
| { | |
| SET_RESTORE_ROUNDF128 (FE_TONEAREST); | |
| if (x == 0 || ix >= 0x7fff0000) /* if x is 0 or inf */ | |
| return sgn == 1 ? -zero : zero; | |
| else if ((__float128) n <= x) | |
| { | |
| /* Safe to use J(n+1,x)=2n/x *J(n,x)-J(n-1,x) */ | |
| if (ix >= 0x412D0000) | |
| { /* x > 2**302 */ | |
| /* ??? Could use an expansion for large x here. */ | |
| /* (x >> n**2) | |
| * Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi) | |
| * Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi) | |
| * Let s=sin(x), c=cos(x), | |
| * xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then | |
| * | |
| * n sin(xn)*sqt2 cos(xn)*sqt2 | |
| * ---------------------------------- | |
| * 0 s-c c+s | |
| * 1 -s-c -c+s | |
| * 2 -s+c -c-s | |
| * 3 s+c c-s | |
| */ | |
| __float128 s; | |
| __float128 c; | |
| sincosq (x, &s, &c); | |
| switch (n & 3) | |
| { | |
| case 0: | |
| temp = c + s; | |
| break; | |
| case 1: | |
| temp = -c + s; | |
| break; | |
| case 2: | |
| temp = -c - s; | |
| break; | |
| case 3: | |
| temp = c - s; | |
| break; | |
| } | |
| b = invsqrtpi * temp / sqrtq (x); | |
| } | |
| else | |
| { | |
| a = j0q (x); | |
| b = j1q (x); | |
| for (i = 1; i < n; i++) | |
| { | |
| temp = b; | |
| b = b * ((__float128) (i + i) / x) - a; /* avoid underflow */ | |
| a = temp; | |
| } | |
| } | |
| } | |
| else | |
| { | |
| if (ix < 0x3fc60000) | |
| { /* x < 2**-57 */ | |
| /* x is tiny, return the first Taylor expansion of J(n,x) | |
| * J(n,x) = 1/n!*(x/2)^n - ... | |
| */ | |
| if (n >= 400) /* underflow, result < 10^-4952 */ | |
| b = zero; | |
| else | |
| { | |
| temp = x * 0.5; | |
| b = temp; | |
| for (a = one, i = 2; i <= n; i++) | |
| { | |
| a *= (__float128) i; /* a = n! */ | |
| b *= temp; /* b = (x/2)^n */ | |
| } | |
| b = b / a; | |
| } | |
| } | |
| else | |
| { | |
| /* use backward recurrence */ | |
| /* x x^2 x^2 | |
| * J(n,x)/J(n-1,x) = ---- ------ ------ ..... | |
| * 2n - 2(n+1) - 2(n+2) | |
| * | |
| * 1 1 1 | |
| * (for large x) = ---- ------ ------ ..... | |
| * 2n 2(n+1) 2(n+2) | |
| * -- - ------ - ------ - | |
| * x x x | |
| * | |
| * Let w = 2n/x and h=2/x, then the above quotient | |
| * is equal to the continued fraction: | |
| * 1 | |
| * = ----------------------- | |
| * 1 | |
| * w - ----------------- | |
| * 1 | |
| * w+h - --------- | |
| * w+2h - ... | |
| * | |
| * To determine how many terms needed, let | |
| * Q(0) = w, Q(1) = w(w+h) - 1, | |
| * Q(k) = (w+k*h)*Q(k-1) - Q(k-2), | |
| * When Q(k) > 1e4 good for single | |
| * When Q(k) > 1e9 good for double | |
| * When Q(k) > 1e17 good for quadruple | |
| */ | |
| /* determine k */ | |
| __float128 t, v; | |
| __float128 q0, q1, h, tmp; | |
| int32_t k, m; | |
| w = (n + n) / (__float128) x; | |
| h = 2 / (__float128) x; | |
| q0 = w; | |
| z = w + h; | |
| q1 = w * z - 1; | |
| k = 1; | |
| while (q1 < 1.0e17Q) | |
| { | |
| k += 1; | |
| z += h; | |
| tmp = z * q1 - q0; | |
| q0 = q1; | |
| q1 = tmp; | |
| } | |
| m = n + n; | |
| for (t = zero, i = 2 * (n + k); i >= m; i -= 2) | |
| t = one / (i / x - t); | |
| a = t; | |
| b = one; | |
| /* estimate log((2/x)^n*n!) = n*log(2/x)+n*ln(n) | |
| * Hence, if n*(log(2n/x)) > ... | |
| * single 8.8722839355e+01 | |
| * double 7.09782712893383973096e+02 | |
| * long double 1.1356523406294143949491931077970765006170e+04 | |
| * then recurrent value may overflow and the result is | |
| * likely underflow to zero | |
| */ | |
| tmp = n; | |
| v = two / x; | |
| tmp = tmp * logq (fabsq (v * tmp)); | |
| if (tmp < 1.1356523406294143949491931077970765006170e+04Q) | |
| { | |
| for (i = n - 1, di = (__float128) (i + i); i > 0; i--) | |
| { | |
| temp = b; | |
| b *= di; | |
| b = b / x - a; | |
| a = temp; | |
| di -= two; | |
| } | |
| } | |
| else | |
| { | |
| for (i = n - 1, di = (__float128) (i + i); i > 0; i--) | |
| { | |
| temp = b; | |
| b *= di; | |
| b = b / x - a; | |
| a = temp; | |
| di -= two; | |
| /* scale b to avoid spurious overflow */ | |
| if (b > 1e100Q) | |
| { | |
| a /= b; | |
| t /= b; | |
| b = one; | |
| } | |
| } | |
| } | |
| /* j0() and j1() suffer enormous loss of precision at and | |
| * near zero; however, we know that their zero points never | |
| * coincide, so just choose the one further away from zero. | |
| */ | |
| z = j0q (x); | |
| w = j1q (x); | |
| if (fabsq (z) >= fabsq (w)) | |
| b = (t * z / b); | |
| else | |
| b = (t * w / a); | |
| } | |
| } | |
| if (sgn == 1) | |
| ret = -b; | |
| else | |
| ret = b; | |
| } | |
| if (ret == 0) | |
| { | |
| ret = copysignq (FLT128_MIN, ret) * FLT128_MIN; | |
| errno = ERANGE; | |
| } | |
| else | |
| math_check_force_underflow (ret); | |
| return ret; | |
| } | |
| __float128 | |
| ynq (int n, __float128 x) | |
| { | |
| uint32_t se; | |
| int32_t i, ix; | |
| int32_t sign; | |
| __float128 a, b, temp, ret; | |
| ieee854_float128 u; | |
| u.value = x; | |
| se = u.words32.w0; | |
| ix = se & 0x7fffffff; | |
| /* if Y(n,NaN) is NaN */ | |
| if (ix >= 0x7fff0000) | |
| { | |
| if ((u.words32.w0 & 0xffff) | u.words32.w1 | u.words32.w2 | u.words32.w3) | |
| return x + x; | |
| } | |
| if (x <= 0) | |
| { | |
| if (x == 0) | |
| return ((n < 0 && (n & 1) != 0) ? 1 : -1) / 0.0Q; | |
| if (se & 0x80000000) | |
| return zero / (zero * x); | |
| } | |
| sign = 1; | |
| if (n < 0) | |
| { | |
| n = -n; | |
| sign = 1 - ((n & 1) << 1); | |
| } | |
| if (n == 0) | |
| return (y0q (x)); | |
| { | |
| SET_RESTORE_ROUNDF128 (FE_TONEAREST); | |
| if (n == 1) | |
| { | |
| ret = sign * y1q (x); | |
| goto out; | |
| } | |
| if (ix >= 0x7fff0000) | |
| return zero; | |
| if (ix >= 0x412D0000) | |
| { /* x > 2**302 */ | |
| /* ??? See comment above on the possible futility of this. */ | |
| /* (x >> n**2) | |
| * Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi) | |
| * Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi) | |
| * Let s=sin(x), c=cos(x), | |
| * xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then | |
| * | |
| * n sin(xn)*sqt2 cos(xn)*sqt2 | |
| * ---------------------------------- | |
| * 0 s-c c+s | |
| * 1 -s-c -c+s | |
| * 2 -s+c -c-s | |
| * 3 s+c c-s | |
| */ | |
| __float128 s; | |
| __float128 c; | |
| sincosq (x, &s, &c); | |
| switch (n & 3) | |
| { | |
| case 0: | |
| temp = s - c; | |
| break; | |
| case 1: | |
| temp = -s - c; | |
| break; | |
| case 2: | |
| temp = -s + c; | |
| break; | |
| case 3: | |
| temp = s + c; | |
| break; | |
| } | |
| b = invsqrtpi * temp / sqrtq (x); | |
| } | |
| else | |
| { | |
| a = y0q (x); | |
| b = y1q (x); | |
| /* quit if b is -inf */ | |
| u.value = b; | |
| se = u.words32.w0 & 0xffff0000; | |
| for (i = 1; i < n && se != 0xffff0000; i++) | |
| { | |
| temp = b; | |
| b = ((__float128) (i + i) / x) * b - a; | |
| u.value = b; | |
| se = u.words32.w0 & 0xffff0000; | |
| a = temp; | |
| } | |
| } | |
| /* If B is +-Inf, set up errno accordingly. */ | |
| if (! finiteq (b)) | |
| errno = ERANGE; | |
| if (sign > 0) | |
| ret = b; | |
| else | |
| ret = -b; | |
| } | |
| out: | |
| if (isinfq (ret)) | |
| ret = copysignq (FLT128_MAX, ret) * FLT128_MAX; | |
| return ret; | |
| } |