|  | void abort (void); | 
|  |  | 
|  | #define N 500 | 
|  | #define M 50 | 
|  |  | 
|  | int X[2*N], Y[2*N], B[2*N]; | 
|  | int A[2*N][2*N], C[2*N][2*N]; | 
|  |  | 
|  | static void __attribute__((noinline,noclone)) | 
|  | init (void) | 
|  | { | 
|  | volatile int i, j; | 
|  |  | 
|  | for (i = 0; i < 2 * N; ++i) | 
|  | { | 
|  | B[i] = 1; | 
|  | X[i] = 1; | 
|  | Y[i] = 1; | 
|  | for (j = 0; j < 2 * N; ++j) | 
|  | { | 
|  | A[i][j] = 1; | 
|  | C[i][j] = 1; | 
|  | } | 
|  | } | 
|  | } | 
|  |  | 
|  | static void __attribute__((noinline,noclone)) | 
|  | foo (void) | 
|  | { | 
|  | int i, j, k; | 
|  |  | 
|  | for (i = 0; i < M; i++) | 
|  | { | 
|  | X[i] = Y[i] + 10; | 
|  | for (j = 0; j < M; j++) | 
|  | { | 
|  | B[j] = A[j][N]; | 
|  | for (k = 0; k < N; k++) | 
|  | { | 
|  | A[j+1][k] = B[j] + C[j][k]; | 
|  | } | 
|  | Y[i+j] = A[j+1][N]; | 
|  | } | 
|  | } | 
|  | } | 
|  |  | 
|  | static void __attribute__((noinline,noclone)) | 
|  | check (void) | 
|  | { | 
|  | volatile int i, j; | 
|  |  | 
|  | for (i = 0; i < 2 * N; ++i) | 
|  | { | 
|  | int expect_x = i < M ? 11 : 1; | 
|  |  | 
|  | if (B[i] != 1 | 
|  | || X[i] != expect_x | 
|  | || Y[i] != 1) | 
|  | abort (); | 
|  |  | 
|  | for (j = 0; j < 2 * N; ++j) | 
|  | { | 
|  | int expect_a = (0 < i && i <= M && j < N) ? 2 : 1; | 
|  |  | 
|  | if (A[i][j] != expect_a | 
|  | || C[i][j] != 1) | 
|  | abort (); | 
|  | } | 
|  | } | 
|  | } | 
|  |  | 
|  | int main(void) | 
|  | { | 
|  | init (); | 
|  | foo (); | 
|  | check (); | 
|  |  | 
|  | return 0; | 
|  | } | 
|  |  | 
|  | /* Check that parallel code generation part make the right answer.  */ | 
|  | /* { dg-final { scan-tree-dump-times "1 loops carried no dependency" 1 "graphite" } } */ | 
|  | /* { dg-final { scan-tree-dump-times "loopfn.0" 4 "optimized" } } */ |