| A variable which requires unique access is being used in more than one closure | |
| at the same time. | |
| Erroneous code example: | |
| ```compile_fail,E0524 | |
| fn set(x: &mut isize) { | |
| *x += 4; | |
| } | |
| fn dragoooon(x: &mut isize) { | |
| let mut c1 = || set(x); | |
| let mut c2 = || set(x); // error! | |
| c2(); | |
| c1(); | |
| } | |
| ``` | |
| To solve this issue, multiple solutions are available. First, is it required | |
| for this variable to be used in more than one closure at a time? If it is the | |
| case, use reference counted types such as `Rc` (or `Arc` if it runs | |
| concurrently): | |
| ``` | |
| use std::rc::Rc; | |
| use std::cell::RefCell; | |
| fn set(x: &mut isize) { | |
| *x += 4; | |
| } | |
| fn dragoooon(x: &mut isize) { | |
| let x = Rc::new(RefCell::new(x)); | |
| let y = Rc::clone(&x); | |
| let mut c1 = || { let mut x2 = x.borrow_mut(); set(&mut x2); }; | |
| let mut c2 = || { let mut x2 = y.borrow_mut(); set(&mut x2); }; // ok! | |
| c2(); | |
| c1(); | |
| } | |
| ``` | |
| If not, just run closures one at a time: | |
| ``` | |
| fn set(x: &mut isize) { | |
| *x += 4; | |
| } | |
| fn dragoooon(x: &mut isize) { | |
| { // This block isn't necessary since non-lexical lifetimes, it's just to | |
| // make it more clear. | |
| let mut c1 = || set(&mut *x); | |
| c1(); | |
| } // `c1` has been dropped here so we're free to use `x` again! | |
| let mut c2 = || set(&mut *x); | |
| c2(); | |
| } | |
| ``` |