| An assignment operator was used on a non-place expression. | |
| Erroneous code examples: | |
| ```compile_fail,E0070 | |
| struct SomeStruct { | |
| x: i32, | |
| y: i32, | |
| } | |
| const SOME_CONST: i32 = 12; | |
| fn some_other_func() {} | |
| fn some_function() { | |
| SOME_CONST = 14; // error: a constant value cannot be changed! | |
| 1 = 3; // error: 1 isn't a valid place! | |
| some_other_func() = 4; // error: we cannot assign value to a function! | |
| SomeStruct::x = 12; // error: SomeStruct a structure name but it is used | |
| // like a variable! | |
| } | |
| ``` | |
| The left-hand side of an assignment operator must be a place expression. A | |
| place expression represents a memory location and can be a variable (with | |
| optional namespacing), a dereference, an indexing expression or a field | |
| reference. | |
| More details can be found in the [Expressions] section of the Reference. | |
| [Expressions]: https://doc.rust-lang.org/reference/expressions.html#places-rvalues-and-temporaries | |
| And now let's give working examples: | |
| ``` | |
| struct SomeStruct { | |
| x: i32, | |
| y: i32, | |
| } | |
| let mut s = SomeStruct { x: 0, y: 0 }; | |
| s.x = 3; // that's good ! | |
| // ... | |
| fn some_func(x: &mut i32) { | |
| *x = 12; // that's good ! | |
| } | |
| ``` |