| The type definition contains some field whose type |
| requires an outlives annotation. Outlives annotations |
| (e.g., `T: 'a`) are used to guarantee that all the data in T is valid |
| for at least the lifetime `'a`. This scenario most commonly |
| arises when the type contains an associated type reference |
| like `<T as SomeTrait<'a>>::Output`, as shown in this example: |
| |
| ```compile_fail,E0309 |
| // This won't compile because the applicable impl of |
| // `SomeTrait` (below) requires that `T: 'a`, but the struct does |
| // not have a matching where-clause. |
| struct Foo<'a, T> { |
| foo: <T as SomeTrait<'a>>::Output, |
| } |
| |
| trait SomeTrait<'a> { |
| type Output; |
| } |
| |
| impl<'a, T> SomeTrait<'a> for T |
| where |
| T: 'a, |
| { |
| type Output = u32; |
| } |
| ``` |
| |
| Here, the where clause `T: 'a` that appears on the impl is not known to be |
| satisfied on the struct. To make this example compile, you have to add |
| a where-clause like `T: 'a` to the struct definition: |
| |
| ``` |
| struct Foo<'a, T> |
| where |
| T: 'a, |
| { |
| foo: <T as SomeTrait<'a>>::Output |
| } |
| |
| trait SomeTrait<'a> { |
| type Output; |
| } |
| |
| impl<'a, T> SomeTrait<'a> for T |
| where |
| T: 'a, |
| { |
| type Output = u32; |
| } |
| ``` |